120 g FeS₂ ni sulfat kislota ishtirokida oksidlash uchun 600 ml KMnO₄ eritmasi sarflandi. Reaksiyada S cho‘kmasi hosil bo‘lgan bo‘lsa, oksidlovchining konsentratsiyasini (N) aniqlang.

n(FeS₂)=1 mol. Fe²⁺→Fe³⁺ (1ē), S⁻¹→S⁰ (1ē·2). Jami ē=3 mol. n(KMnO₄·ē)=N·V ⇒ N=3/0,6=5.

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