34 ℃ haroratdagi 0,05 g gaz namunasi 100 ml hajmli probirkada 600 mm Hg ust. bosim beradi. Bu qanday gaz?
- Xlor
- Metan
- Kislorod
- Vodorod
📝 Detailed explanation
PV = nRT → n = PV/(RT)P = 600 mmHg = 600/760 atm ≈ 0,789 atm
V = 100 ml = 0,1 L
T = 34°C = 307 K
R = 0,0821 L·atm/(mol·K)
n = (0,789 × 0,1)/(0,0821 × 307) = 0,0789/25,2 ≈ 0,00313 mol
M = m/n = 0,05/0,00313 ≈ 16 g/mol
16 g/mol — bu metanning (CH₄) molyar massasi.