40% li (ρ=1,25 g/ml) eritma 5 N li bo‘lsa, erigan moddani toping. Fe₂(SO₄)₃ Fe(NO₃)₃ NaOH CaBr₂ Show answer 📝 Detailed explanation N = ω·ρ·1000/Mekv. Mekv = 0,4·1250/5 = 100. CaBr₂: M=200, ekv=2 ⇒ Mekv=100. To‘g‘ri.
