896 ml (n.sh.) atsetilen gidrogenlanishidan hosil bo‘lgan gazlar aralashmasi 240 g 2% li bromli suvni to‘liq rangsizlantiradi va natijada 3,46 g tetrabromid hosil bo‘ladi. Gidrogenlanishdan keyingi gazlar aralashmasining o‘rtacha molyar massasini (g/mol) aniqlang.

28,5
26,5
22,8
27,5

📝 Detailed explanation

n(C₂H₂)dastlab = 0,896/22,4 = 0,04 mol. n(Br₂)umum = 240·0,02/160 = 0,03 mol. C₂H₂Br₄ massasi 3,46 g ⇒ n=3,46/346=0,01 mol (asetilen, 2Br₂ qo‘shiladi → 0,02 mol Br₂ sarflanadi). Qolgan Br₂ = 0,01 mol etilen bilan (1:1) reaksiyada: n(C₂H₄)=0,01 mol. Qolgan etan = 0,04 − 0,01 − 0,01 = 0,02 mol. Massa: 26·0,01+28·0,01+30·0,02 = 1,14 g; n umum = 0,04 mol ⇒ M̄ = 28,5 g/mol.

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