A 10 L mixture of methane and propane requires 41 L of oxygen for complete combustion. Determine the volume of methane in the mixture.
- 3 L
- 7 L
- 5 L
- 4 L
📝 Detailed explanation
x + y = 10 (x is methane, y is propane).CH₄ + 2O₂ → CO₂ + 2H₂O.
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
2x + 5y = 41.
2(10 - y) + 5y = 41 => 20 - 2y + 5y = 41.
3y = 21 => y = 7 L (Propane).
x = 10 - 7 = 3 L (Methane).