A mixture of methane and propane with a total volume of 10 L requires 38 L of oxygen for complete combustion. Find the volume of propane in the original mixture.
- 6 L
- 4 L
- 5 L
- 2 L
📝 Detailed explanation
Let V(CH₄) = x, V(C₃H₈) = y.x + y = 10.
CH₄ + 2O₂ → CO₂ + 2H₂O.
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
2x + 5y = 38.
2(10-y) + 5y = 38.
20 - 2y + 5y = 38.
3y = 18.
y = 6 L.