Amino acids formed from the hydrolysis of 0.01 mol of a polypeptide reacted with 0.3 kg of a 16% NaOH solution. Determine how many amino acid residues the polypeptide consists of?
- 120
- 100
- 200
- 150
📝 Detailed explanation
Mass NaOH = 300 × 0.16 = 48 g.n(NaOH) = 48 / 40 = 1.2 mol.
One amino acid reacts with one NaOH.
Total amino acids = 1.2 mol.
Residues = n(Amino acids) / n(Polypeptide) = 1.2 / 0.01 = 120.