Calculate the mass of a divalent metal oxide (MO) that reacts with 200 ml of 1 M HNO₃ to form a salt and water. The atomic mass of the metal M is 24.
- 4 g
- 8 g
- 2 g
- 5.6 g
📝 Detailed explanation
MO + 2HNO₃ → M(NO₃)₂ + H₂O.n(HNO₃) = 0.2 L * 1 M = 0.2 mol.
n(MO) = 0.2 / 2 = 0.1 mol.
M(MO) = 24 + 16 = 40 g/mol.
Mass MO = 0.1 * 40 = 4 g.