Calculate the volume of 1 M sodium hydroxide solution needed to completely neutralize 50 ml of 0.5 M sulfuric acid.
- 25 ml
- 50 ml
- 100 ml
- 75 ml
📝 Detailed explanation
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.n(H₂SO₄) = 0.05 * 0.5 = 0.025 mol.
n(NaOH) needed = 0.025 * 2 = 0.05 mol.
V(NaOH) = 0.05 / 1 = 0.05 L = 50 ml.