Calculate the volume of oxygen required for the complete combustion of a 10 L mixture of Carbon Monoxide and Methane, if the mixture has a density of 0.982 g/l at STP.
- 12.5 L
- 15 L
- 10 L
- 20 L
📝 Detailed explanation
M_avg = 0.982 * 22.4 = 22 g/mol.Let x = volume fraction of CH₄, (1-x) = fraction of CO.
16x + 28(1-x) = 22
16x + 28 - 28x = 22 => 12x = 6 => x = 0.5.
V(CH₄) = 5 L, V(CO) = 5 L.
CH₄ + 2O₂ → CO₂ + 2H₂O (Needs 2*5 = 10 L O₂)
CO + 0.5O₂ → CO₂ (Needs 0.5*5 = 2.5 L O₂)
Total O₂ = 10 + 2.5 = 12.5 L.