Determine the mass of Silver formed when 0.1 mol of glucose reacts with excess Tollens' reagent.
- 21.6 g
- 10.8 g
- 43.2 g
- 5.4 g
📝 Detailed explanation
1 mol of Glucose reduces 2 mol of Ag⁺ to Ag.n(Ag) = 0.1 * 2 = 0.2 mol.
Mass Ag = 0.2 * 108 = 21.6 g.
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