Find the molar concentration of a solution prepared by mixing 200 ml of 0.1 M hydrochloric acid and 300 ml of 0.2 M hydrochloric acid.
- 0.15 M
- 0.16 M
- 0.18 M
- 0.25 M
📝 Detailed explanation
n1 = 0.2 * 0.1 = 0.02 mol.n2 = 0.3 * 0.2 = 0.06 mol.
n_total = 0.02 + 0.06 = 0.08 mol.
V_total = 0.2 + 0.3 = 0.5 L.
Molarity = 0.08 / 0.5 = 0.16 M.