Hisoblang: √(34 − √(27 · √(13 − √(16))))
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4
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5
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7
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2
📝 Detailed explanation
Eng ichki ildizdan boshlab ketma-ket hisoblaymiz: √(16) = 4; keyin √(13 − 4) = √(9) = 3; keyin √(27 × 3) = √(81) = 9; oxirida √(34 − 9) = √(25) = 5.
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