How many liters of oxygen are required to burn 2 moles of Ethanol?
- 134.4 L
- 67.2 L
- 44.8 L
- 22.4 L
📝 Detailed explanation
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O.n(O₂) = 2 mol * 3 = 6 mol.
Volume O₂ = 6 * 22.4 = 134.4 L.
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