How many moles of calcium nitrate must be decomposed to produce oxygen in a mass equal to the mass of the gas formed when 1/3 mole of aluminum carbide is hydrolyzed?
- 0.5
- 1
- 0.8
- 0.4
📝 Detailed explanation
Hydrolysis: Al₄C₃ + 12H₂O → 4Al(OH)₃ + 3CH₄.1/3 mol Al₄C₃ produces 1 mol CH₄, which weighs 16 g.
Decomposition: Ca(NO₃)₂ → CaO + 2NO₂ + 0.5O₂.
We need 16 g of O₂, which is 0.5 mol.
From reaction, 1 mol of salt produces 0.5 mol O₂.
Therefore, 1 mole of calcium nitrate is required.