How many moles of KMnO₄ are required to oxidize 0.5 moles of FeSO₄ in the presence of sulfuric acid?
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0.5
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0.1
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0.2
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2.5
📝 Detailed explanation
Redox: 10FeSO₄ + 2KMnO₄ + 8H₂SO₄ → 5Fe₂(SO₄)₃ + 2MnSO₄ + K₂SO₄ + 8H₂O.
The molar ratio Fe²⁺ : MnO₄⁻ is 5:1.
Moles KMnO₄ = 0.5 / 5 = 0.1 mol.
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