In the combustion of a mixture of 10 g Hydrogen and 80 g Oxygen, what is the maximum mass of water that can be formed?
- 90 g
- 18 g
- 100 g
- 80 g
📝 Detailed explanation
2H₂ + O₂ → 2H₂O.n(H₂) = 10 / 2 = 5 mol.
n(O₂) = 80 / 32 = 2.5 mol.
Ratio H₂:O₂ is exactly 2:1 (5:2.5). Neither is limiting.
n(H₂O) = 5 mol.
Mass H₂O = 5 * 18 = 90 g.