In the following reaction: 3Cu + 8HNO₃(dilute) → 3Cu(NO₃)₂ + 2NO + 4H₂O, how many electrons are transferred in total per 3 moles of Copper?
2
4
6
8
📝 Detailed explanation
Copper changes from 0 to +2. For 3 moles of Cu, 3 * 2 = 6 electrons are lost. Nitrogen changes from +5 (in HNO₃) to +2 (in NO). For 2 moles of NO, 2 * 3 = 6 electrons are gained. The total transferred is 6.
