Используя данные:
H₂C=CH₂ + 3O₂ → 2CO₂ + 2H₂O − 345 ккал;
EC=O=200; EC=C=150; EO=O=115; EC–H=100 ккал/моль,
найдите энергию связи H–O (ккал/моль).

  1. 120
  2. 90
  3. 100
  4. 110

📝 Detailed explanation

ΔH = (150 + 4·100 + 3·115) − (4·200 + 4·E_{H–O}) = −345; 895 − 800 − 4E = −345 → 4E = 440 → E = 110.
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