Какова концентрация молекул газа при температуре 400 K и давлении 138 кПа (м⁻³)?

  1. 2,5·10²⁵
  2. 5·10²⁵
  3. 1,38·10⁷
  4. 2,76·10⁶

📝 Detailed explanation

p = nkT ⟹ n = p/(kT).
n = 138000 / (1,38·10⁻²³ · 400) = 138000 / 5,52·10⁻²¹ = 2,5·10²⁵ м⁻³.
13 / 30 (43%)
Question 13 of 30
← Previous → Next Space — Show answer

🎯 Take a test on the topic «Тест по физике Основы молекулярно-кинетической теории строения вещества 9 класс»

This topic contains 30 questions. Test your knowledge!

🔐 Log in to take the test

📚 All tests by subject «Физика»

View all collections and topics in Физика

Go to subject →

Report an error

Answers are unavailable

This test collection is closed. To get full access, please purchase 🌟 premium

Contact by email