Massasi 16,8 g bo‘lgan noma’lum alken yetarli miqdordagi kaliy permanganatning suvli eritmasi bilan oksidlanganda 1/5 mol cho‘kma hosil bo‘ldi. Reaksiya natijasida hosil bo‘lgan organik moddani aniqlang.

3R-CH=CH-R'+2KMnO₄+4H₂O→3glikol+2MnO₂+2KOH. n(MnO₂)=0,2 ⇒ n(alken)=0,3 mol. M=16,8/0,3=56 ⇒ C₄H₈ ⇒ glikol C₄H₈(OH)₂.

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