N va H atomlar soni 3 : 1 bo‘lgan azot va ammiak aralashmasi yondirilgandan so‘ng idishda 9 l N₂ bo‘lsa, dastlabki aralashma hajmini toping. (o‘lchashlar bir xil sharoitda bajarilgan)

Aralashma: x mol N₂ + y mol NH₃. N: 2x+y; H: 3y. (2x+y)/(3y)=3/1 ⇒ 2x+y=9y ⇒ x=4y. Yonishdan keyin N₂: x+y/2 = 9 l. 4y+0,5y=9 ⇒ y=2, x=8 ⇒ jami 10 l.

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