[Olympiad] A reaction 2NO + O₂ → 2NO₂ was studied and the following data was obtained:
Exp 1: [NO]=0.1, [O₂]=0.1, Rate=0.001
Exp 2: [NO]=0.2, [O₂]=0.1, Rate=0.004
Exp 3: [NO]=0.1, [O₂]=0.2, Rate=0.002.
What is the rate law?
- Rate = k[NO][O₂]
- Rate = k[NO]²[O₂]
- Rate = k[NO][O₂]²
- Rate = k[NO]²[O₂]²
📝 Detailed explanation
Comparing Exp 1 and 2: [NO] doubles, Rate quadruples (2²=4), so order for NO is 2.Comparing Exp 1 and 3: [O₂] doubles, Rate doubles (2¹=2), so order for O₂ is 1.
Rate = k[NO]²[O₂].