[Olympiad] Calculate the pH of a 0.10 M solution of Acetic acid (CH₃COOH). (Ka = 1.8 × 10⁻⁵)
- 1.00
- 2.37
- 2.87
- 4.74
📝 Detailed explanation
[H⁺] = √(Ka * C) = √(1.8 × 10⁻⁵ * 0.1) = √(1.8 × 10⁻⁶) = 1.34 × 10⁻³ M.pH = -log(1.34 × 10⁻³) ≈ 2.87.
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