[Olympiad] Calculate the pH of a buffer solution that is 0.10 M in NH₃ and 0.20 M in NH₄Cl. (Kb for NH₃ = 1.8 × 10⁻⁵)
-
4.74
-
9.26
-
8.96
-
9.56
📝 Detailed explanation
pKb = -log(1.8 × 10⁻⁵) = 4.74. pOH = pKb + log([Salt]/[Base]) = 4.74 + log(0.2/0.1) = 4.74 + 0.30 = 5.04.
pH = 14 - 5.04 = 8.96.
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