Quyidagi oksidlanish-qaytarilish reaksiyalarida 36 g dan suv hosil bo‘lsa, sarflangan oksidlovchilarning massa (g) farqini aniqlang.
1) H₂S + K₂Cr₂O₇ + H₂SO₄ → Cr₂(SO₄)₃ + S + K₂SO₄ + H₂O
2) H₂O₂ + KMnO₄ + H₂SO₄ → MnSO₄ + O₂ + K₂SO₄ + H₂O
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5
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5,4
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10
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27
📝 Detailed explanation
n(H₂O) = 36/18 = 2 mol har biri uchun. 1-tenglama: 3H₂S+K₂Cr₂O₇+4H₂SO₄→Cr₂(SO₄)₃+3S+K₂SO₄+7H₂O ⇒ n(K₂Cr₂O₇)=2/7 mol; m=294·2/7=84 g. 2-tenglama: 5H₂O₂+2KMnO₄+3H₂SO₄→2MnSO₄+5O₂+K₂SO₄+8H₂O ⇒ n(KMnO₄)=2·2/8=0,5 mol; m=158·0,5=79 g. Farq = 84 − 79 = 5 g.
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