Tarkibi KAl(SO₄)₂·nH₂O bo'lgan 94,8 g achchiqtosh bariy xlorid eritmasida eritilganda 93,2 g oq cho'kma hosil bo'ldi. n ning qiymatini toping.

  1. 12
  2. 9
  3. 8
  4. 18

📝 Detailed explanation

Cho'kma — BaSO₄, M = 233 g/mol.
ν(BaSO₄) = 93,2/233 = 0,4 mol.
1 mol achchiqtoshda 2 mol SO₄²⁻ bor → ν(achchiqtosh) = 0,4/2 = 0,2 mol.
Mol massasi: M = 94,8/0,2 = 474 g/mol.
M(KAl(SO₄)₂) = 39 + 27 + 2·96 = 258 g/mol.
n·18 = 474 − 258 = 216 → n = 12.
Javob: 12.
19 / 36 (53%)
Question 19 of 36
← Previous → Next Space — Show answer

🎯 Take a test on the topic «7-sinf Tabiiy fanlar 2026 AL-XORAZMIY nomidagi olimpiadaning TUMAN bosqichi»

This topic contains 36 questions. Test your knowledge!

🔐 Log in to take the test

📚 All tests by subject «Tabiiy fanlar (Science)»

View all collections and topics in Tabiiy fanlar (Science)

Go to subject →

Report an error

Answers are unavailable

This test collection is closed. To get full access, please purchase 🌟 premium

Contact by email