Termokimyoviy tenglamalar berilgan:
Br₂(suyuq) + F₂(gaz) → 2BrF(gaz) ΔH° = -188 kJ
Br₂(suyuq) + 3F₂(gaz) → 2BrF₃(gaz) ΔH° = -768 kJ
Quyidagi reaksiya uchun entalpiyani hisoblang:
BrF(gaz) + F₂(gaz) → BrF₃(gaz) ΔH° = ?
- -956 kJ
- -580 kJ
- -478 kJ
- -290 kJ
📝 Detailed explanation
2-reaksiyadan 1-reaksiyani ayiramiz:(Br₂ + 3F₂ → 2BrF₃) - (Br₂ + F₂ → 2BrF)
= 2BrF + 2F₂ → 2BrF₃
ΔH = -768 - (-188) = -580 kJ
2 ga bo'lamiz: BrF + F₂ → BrF₃
ΔH = -580/2 = -290 kJ.