The specific heat capacity of water is 4.18 J/g·°C. How much energy is required to heat 100 g of water from 20 °C to 70 °C?
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4.18 kJ
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17.5 kJ
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20.9 kJ
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41.8 kJ
📝 Detailed explanation
q = m * c * ΔT. q = 100g * 4.18 J/g·°C * (70 - 20)°C = 100 * 4.18 * 50 = 20,900 J = 20.9 kJ.
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