What is the pH of a 0.001 M solution of Barium Hydroxide Ba(OH)₂, assuming complete dissociation?
- 3.0
- 11.0
- 11.3
- 11.7
📝 Detailed explanation
[OH⁻] = 2 * [Ba(OH)₂] = 0.002 M.pOH = -log(0.002) ≈ 2.7.
pH = 14 - 2.7 = 11.3.
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