What is the volume of 2 M KOH needed to react with 11.2 L of CO₂ (at STP) to form potassium carbonate?
-
500 ml
-
250 ml
-
1000 ml
-
100 ml
📝 Detailed explanation
2KOH + CO₂ → K₂CO₃ + H₂O.
n(CO₂) = 11.2 / 22.4 = 0.5 mol.
n(KOH) needed = 0.5 * 2 = 1 mol.
Volume KOH = 1 mol / 2 M = 0.5 L = 500 ml.
← Previous
→ Next
Space — Show answer
🎯 Take a test on the topic «CAU Admission Test Sample Questions 7»
This topic contains 30 questions.
Test your knowledge!
🔐 Log in to take the test
📚 All tests by subject «Bio+Chem»
View all collections and topics in Bio+Chem
Go to subject →
