X + 2NaOH → 2NH₃ + 2H₂O + Na₂S. Вычислите молярную массу (г/моль) X в данной реакции.

  1. 68
  2. 51
  3. 96
  4. 66

📝 Detailed explanation

Уравнивая, X должен содержать 2N, 8H, 1S → (NH₄)₂S. M = 2·18 + 32 = 68 г/моль.
6 / 84 (7%)
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