A 16 g sample of impure Calcium Carbide (CaC₂) reacts with water to produce 4.48 liters of acetylene gas (at STP). What is the percentage purity of the calcium carbide?
- 80%
- 90%
- 75%
- 100%
📝 Batafsil tushuntirish
n(C₂H₂) = 4.48 / 22.4 = 0.2 mol.n(CaC₂) pure = 0.2 mol.
Mass pure CaC₂ = 0.2 * 64 = 12.8 g.
Purity = (12.8 / 16) * 100 = 80%.