A mixture of 4 grams of Hydrogen (H₂) and 64 grams of Oxygen (O₂) is ignited to form water. What is the maximum mass of water that can be produced?
- 18 g
- 36 g
- 72 g
- 80 g
📝 Batafsil tushuntirish
Reaction: 2H₂ + O₂ → 2H₂O.Moles of H₂ = 4g / 2g/mol = 2 moles.
Moles of O₂ = 64g / 32g/mol = 2 moles.
According to stoichiometry, 2 moles of H₂ need 1 mole of O₂. H₂ is the limiting reagent. 2 moles of H₂ will produce 2 moles of H₂O. Mass = 2 * 18g/mol = 36 g.