Calculate the standard enthalpy change (ΔH°) for the reaction: 2H₂(g) + O₂(g) → 2H₂O(l) given that the standard enthalpy of formation of H₂O(l) is -285.8 kJ/mol.
- -142.9 kJ
- -285.8 kJ
- -571.6 kJ
- +571.6 kJ
📝 Detailed explanation
ΔH° = ΣΔH°f(products) - ΣΔH°f(reactants).ΔH° = [2 * (-285.8)] - [0 + 0] = -571.6 kJ.