How many grams of water are required to react with 14 g of calcium carbide to produce acetylene gas?
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3.6 g
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7.87 g
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18 g
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9 g
📝 Detailed explanation
CaC₂ + 2H₂O → Ca(OH)₂ + C₂H₂.
Moles CaC₂ = 14 / 64 = 0.21875 mol.
Moles H₂O needed = 0.21875 × 2 = 0.4375 mol.
Mass H₂O = 0.4375 × 18 = 7.875 g.
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