How many liters of oxygen are required to burn 2 moles of Ethanol?

134.4 L
67.2 L
44.8 L
22.4 L

📝 Detailed explanation

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O.
n(O₂) = 2 mol * 3 = 6 mol.
Volume O₂ = 6 * 22.4 = 134.4 L.

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