Iron reacts with Hydrochloric acid as follows: Fe + 2HCl → FeCl₂ + H₂. If 28 g of Iron reacts with excess acid and only 0.8 g of Hydrogen gas is collected, what is the percentage yield? (Ar: Fe=56, H=1)
- 40%
- 80%
- 90%
- 100%
📝 Detailed explanation
Theoretical: Moles of Fe = 28/56 = 0.5 mol. Moles of H₂ expected = 0.5 mol.Theoretical mass of H₂ = 0.5 mol × 2g/mol = 1.0 g.
% Yield = (Actual/Theoretical) × 100 = (0.8 / 1.0) × 100 = 80%.