Используя таблицу, вычислите число электронов в ионе X³⁺.
Ион X³⁺: N(p) = a, N(n) = a + 6, N(X) = 54.

  1. 27
  2. 24
  3. 21
  4. 18

📝 Detailed explanation

N(X) = массовое число = a + (a+6) = 2a + 6 = 54 → a = 24 (Cr). Электронов в X³⁺: 24 − 3 = 21.
31 / 71 (44%)
Question 31 of 71
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