[Olympiad] Calculate the pH of a 0.1 M solution of Cyanic acid (HCN). (Ka = 4.9 × 10⁻¹⁰)
-
2.56
-
4.12
-
5.15
-
7.00
📝 Detailed explanation
[H⁺] = √(Ka × C) = √(4.9 × 10⁻¹⁰ × 0.1) = √(4.9 × 10⁻¹¹) = 7.0 × 10⁻⁶ M.
pH = -log(7.0 × 10⁻⁶) = 6 - 0.845 = 5.155 ≈ 5.16.
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