[Olympiad] The solubility product (Ksp) of Silver chromate (Ag₂CrO₄) is 1.1 × 10⁻¹². Calculate its molar solubility in pure water.
- 6.5 × 10⁻⁵ M
- 6.5 × 10⁻⁵ M
- 1.1 × 10⁻⁶ M
- 1.3 × 10⁻⁴ M
📝 Detailed explanation
Ag₂CrO₄ ⇌ 2Ag⁺ + CrO₄²⁻. Ksp = (2s)²(s) = 4s³.s = ∛(1.1 × 10⁻¹² / 4) = ∛(2.75 × 10⁻¹³) = 6.5 × 10⁻⁵ M.