Степень окисления +4 сера проявляет в соединениях:

  1. H2SO4, H2S
  2. Nа2S, H2SO3
  3. H2SO3, SO2

📝 Detailed explanation

В SO2:
O = −2
2 × (−2) = −4
Значит, S = +4
В H2SO3:
H = +1 -> (2 × +1 = +2)
O = −2 -> (3 × −2 = −6)
+2 + x − 6 = 0
x = +4
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Question 21 of 23
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