Tarkibida 13,2 g kislotalar (nitrat va sulfat) tutgan 77,2 g eritmaga yetarli miqdorda bariy nitrat tuzi qo'shilganda 80 g 20 % li nitrat kislota eritmasi olindi. Qo'shilgan bariy nitrat massasini (g) toping.
- 26,1
- 29
- 13,05
- 14,5
📝 Detailed explanation
Reaksiya: H₂SO₄ + Ba(NO₃)₂ → BaSO₄↓ + 2HNO₃.Yakuniy eritmadagi HNO₃: 80·0,2 = 16 g = 16/63 mol ≈ 0,254 mol.
Aytaylik dastlab x g HNO₃ va y g H₂SO₄ bor: x + y = 13,2.
Reaksiyada hosil bo'lgan HNO₃: 2·(y/98)·63 = 126y/98 = 9y/7 g.
Yakuniy HNO₃: x + 9y/7 = 16. (1)
x + y = 13,2 → x = 13,2 − y. (2)
13,2 − y + 9y/7 = 16 → 13,2 + 2y/7 = 16 → 2y/7 = 2,8 → y = 9,8 g H₂SO₄.
ν(H₂SO₄) = 9,8/98 = 0,1 mol → ν(Ba(NO₃)₂) = 0,1 mol.
Massasi: 0,1·261 = 26,1 g.
Javob: 26,1 g.