What volume of 0.1 M KMnO₄ is required to react with 0.5 moles of Fe²⁺ in an acidic solution?
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500 ml
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100 ml
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1000 ml
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200 ml
📝 Detailed explanation
5Fe²⁺ + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O.
Moles MnO₄⁻ = 0.5 / 5 = 0.1 mol.
Volume = 0.1 / 0.1 = 1 L = 1000 ml.
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