What volume of 0.1 M KMnO₄ is required to react with 0.5 moles of Fe²⁺ in an acidic solution?

  1. 500 ml
  2. 100 ml
  3. 1000 ml
  4. 200 ml

📝 Detailed explanation

5Fe²⁺ + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O.
Moles MnO₄⁻ = 0.5 / 5 = 0.1 mol.
Volume = 0.1 / 0.1 = 1 L = 1000 ml.
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Question 28 of 30
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