What volume of CO₂ (at STP) is produced by the complete thermal decomposition of 10 g of Calcium carbonate (CaCO₃)? (Molar mass of CaCO₃ = 100 g/mol)
- 1.12 L
- 2.24 L
- 4.48 L
- 22.4 L
📝 Detailed explanation
Reaction: CaCO₃(s) → CaO(s) + CO₂(g).Moles of CaCO₃ = 10 / 100 = 0.1 mol.
According to stoichiometry, 0.1 mol of CaCO₃ produces 0.1 mol of CO₂.
Volume = 0.1 mol * 22.4 L/mol = 2.24 L.