When 0.6 moles of a mixture of equal molar proportions of alkane and hydrogen were burned, 1.2 moles of water were produced. Identify the alkane.
- Ethane
- Methane
- Butane
- Propane
📝 Detailed explanation
Mixture has 0.3 mol alkane and 0.3 mol H₂.Burning 0.3 mol H₂ produces 0.3 mol H₂O.
Remaining H₂O from alkane = 1.2 - 0.3 = 0.9 mol.
1 mol of alkane produces 0.9 / 0.3 = 3 mol H₂O.
Alkane CₙH₂ₙ₊₂ produces (n+1) moles of H₂O.
n + 1 = 3, so n = 2.
The alkane is Ethane.