A certain amount of a divalent metal reacts with excess dilute nitric acid to produce 4.48 liters of nitrogen monoxide gas at STP. If 19.2 grams of the metal was consumed, identify the metal.

  1. Cu
  2. Mg
  3. Fe
  4. Zn

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Reaction: 3M + 8HNO₃ → 3M(NO₃)₂ + 2NO + 4H₂O.
Moles of NO = 4.48 / 22.4 = 0.2 mol.
Molar ratio M : NO is 3 : 2.
Moles of Metal = 0.2 × (3 / 2) = 0.3 mol.
Molar mass M = mass / moles = 19.2 / 0.3 = 64 g/mol.
The metal is Copper.
18 / 30 (60%)
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