A mixture of CO and CO₂ has a density of 1.518 g/l at STP. Find the mass fraction of CO₂ in the mixture.
- 50%
- 25%
- 75%
- 40%
📝 Batafsil tushuntirish
M_avg = 1.518 * 22.4 = 34 g/mol.Let x be mole fraction of CO₂.
44x + 28(1-x) = 34.
16x = 6, so x = 0.375.
In 1 mol: mass CO₂ = 0.375 * 44 = 16.5 g.
Mass CO = 0.625 * 28 = 17.5 g.
Wait, total mass = 16.5 + 17.5 = 34 g.
Mass fraction CO₂ = 16.5 / 34 ≈ 0.485.
Options: 50% is the closest standard result for these parameters.