Balance the following equation in an acidic medium: Cr₂O₇²⁻ + Fe²⁺ → Cr³⁺ + Fe³⁺. What is the coefficient of Fe²⁺ in the balanced equation?

  1. 1
  2. 3
  3. 6
  4. 7

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Half-reactions:
1) Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O
2) Fe²⁺ → Fe³⁺ + 1e⁻.
To equalize electrons, multiply the second reaction by 6. The coefficient for Fe²⁺ is 6.
4 / 50 (8%)
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