Determine the pH of a 0.005 M solution of Barium hydroxide.
- 12
- 2
- 11
- 13
📝 Batafsil tushuntirish
Ba(OH)₂ → Ba²⁺ + 2OH⁻.[OH⁻] = 2 * 0.005 = 0.01 M.
pOH = -log(0.01) = 2.
pH = 14 - 2 = 12.
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